Try these, if you get stuck ) Dont forget to ask. I dont think it would be hard to proceed from this point on. So since you know its the reflection of the left curve (a known curve by now) and you know a point it meets, and you know the line of reflection. Look closely, or better yet draw the line $x=-9$ and this will become clear to you. Now the curve at the Right side, it approximately looks like the mirror image of the curve on the left side at a vertical line (which I will tell in a moment) and they have mentioned a point it meets, so I would say the right hand side is the reflection of the curve on the left side about the line $x=-9$ (the line of reflection). So there you have it a 4th equation, now you can solve the 4 equations, find the four unknowns and plot this curve.
NOW we want a formula (not an expression) so we should know that the gradient of line A (which you should know by now) multiplied by the T is equal to -1. Then to this when you substitute x=-3 to this function ($dy/dx$) you get an expression with a bunch of unknowns. Which gives:Īnd in order to get the 4th equation you should know that, the line A is normal to the point (-3,9) on the curve, this means that you need to differentiate the function $y=a+c log_b(dx)$ and then you get the first derivative which is a function. So the first three equations will be subsituting the 3 points that they have given into the equation. Mark the image with the Desmos Activity: Grade 6: Polygons on a. We know three points on the curve which are $(-27,17)$, $(-9,3)$ and $(-3,9)$Īnd we know its in the form $y=a+c log_b(dx)$īut there are 4 unkowns you need to solve for a,b,c,d. Graph these points in order to create the picture of a much-beloved. Now for the curves, lets first look at curve on the right side Il put $(-3,9)$īecause you know m you can find c, and this is the equation of line A. Now plugin these and then to now since you know the value of m, to find c Where m is the gradient and c is the intercept. The equation of a striaght line is $y=mx+c$ Now to find the line of A and B is pretty simple, Il do for one (Line A) to demonstrate it. The line made by joining points $(-17,0)$ and $(-3,9)$ as Line AĪnd the line made by joining points $(-12,0)$ and $(-3,9)$ as Line BĪnd the left curve and right curve as shown in the diagram.
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